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We have learned the basic concept of functions in Visual Basic 2010 ,
in particular the usage of the MsgBox and InputBox functions in Lesson
12. I. In fact, I have already shown you a few string manipulation
functions in Lesson 8, they are the Len function, the Left function and
the Right Function. In this lesson, we will learn how to write codes
involving other string manipulation functions in Visual Basic 2010.
13.1 The Mid Function
13.2 The Right Function
The Right function extracts the right portion of a phrase. The syntax is
Microsoft.Visualbasic.Right (“Phrase”, n)
Where n is the starting position from the right of the phase where the portion of the phrase is going to be extracted. For example:
Microsoft.Visualbasic.Right (“Visual Basic”, 4) = asic
Example 13.2: The following code extracts the right portion any phrase entered by the user.
Private Sub Button1_Click (ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myword As String
myword = TextBox1.Text
Label1.Text = Microsoft.VisualBasic.Right (myword, 4)
End Sub
13.3 The Left Function
The Left function extracts the left portion of a phrase. The syntax is
Microsoft.Visualbasic.Right (“Phrase”, n)
Where n is the starting position from the left of the phase where the portion of the phrase is going to be extracted. For example:
Microsoft.Visualbasic.Left(“Visual Basic”, 4) = asic
Example 13.3: The following code extracts the left portion any phrase entered by the user.
Private Sub Button1_Click (ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myword As String
myword = TextBox1.Text
Label1.Text = Microsoft.VisualBasic.Left (myword, 4)
End Sub
13.4 The Trim Function
The Trim function trims the empty spaces on both side of the phrase. The format is
Trim(“Phrase”)
.For example, Trim (” Visual Basic 2010 “) = Visual basic 2010
Example 13.4
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myPhrase As String
myPhrase = Microsoft.VisualBasic.InputBox(“Enter your phrase”)
Label1.Text = Trim(myPhrase)
End Sub
13.5 The Ltrim Function
The Ltrim function trims the empty spaces of the left portion of the phrase. The syntax is
Ltrim(“Phrase”)
.For example,
Ltrim (” Visual Basic 2010 “)= Visual basic 2010
13.6 The Rtrim Function
The Rtrim function trims the empty spaces of the right portion of the phrase. The syntax is
Rtrim(“Phrase”)
.For example,
Rtrim (“Visual Basic “) = Visual Basic
13.7 The InStr function
The InStr function looks for a phrase that is embedded within the original phrase and returns the starting position of the embedded phrase. The syntax is
Instr (n, original phase, embedded phrase)
Where n is the position where the Instr function will begin to look for the embedded phrase. For example
Instr(1, “Visual Basic 2010 “,”Basic”)=8
*The function returns a numeric value.
You can write a program code as shown below:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Label1.Text = InStr(1, “Visual Basic 2010”, “Basic”)
End Sub
13.8 The Ucase and the Lcase Functions
The Ucase function converts all the characters of a string to capital letters. On the other hand, the Lcase function converts all the characters of a string to small letters.
The format is
Microsoft.VisualBasic.UCase(Phrase)
Microsoft.VisualBasic.LCase(Phrase)
For example,
Microsoft.VisualBasic.Ucase(“Visual Basic 2010”) =VISUAL BASIC 2010
Microsoft.VisualBasic.Lcase(“Visual Basic 2010”) =visual basic 2010
13.9 The Chr and the Asc functions
The Chr function returns the string that corresponds to an ASCII code while the Asc function converts an ASCII character or symbol to the corresponding ASCII code. ASCII stands for “American Standard Code for Information Interchange”. Altogether there are 255 ASCII codes and as many ASCII characters. Some of the characters may not be displayed as they may represent some actions such as the pressing of a key or produce a beep sound. The syntax of the Chr function is
Chr(charcode)
and the syntax of the Asc function is
Asc(Character)
The following are some examples:
Chr(65)=A, Chr(122)=z, Chr(37)=% ,
Asc(“B”)=66, Asc(“&”)=38
13.1 The Mid Function
The Mid function is used to retrieve a part of text form a given phrase. The syntax of the Mid Function is
Mid(phrase, position,n)
where
phrase is the string from which a part of text is to be retrieved.
position is the starting position of the phrase from which the retrieving process begins.
n is the number of characters to retrieve.
where
phrase is the string from which a part of text is to be retrieved.
position is the starting position of the phrase from which the retrieving process begins.
n is the number of characters to retrieve.
Example 13.1:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myPhrase As String
myPhrase = Microsoft.VisualBasic.InputBox(“Enter your phrase”)
Label1.Text = Mid(myPhrase, 2, 6)
End Sub
* In this example, when the user clicks the command button, an input box will pop up asking the user to input a phrase. After a phrase is entered and the OK button is pressed, the label will show the extracted text starting from position 2 of the phrase and the number of characters extracted is 6.
Dim myPhrase As String
myPhrase = Microsoft.VisualBasic.InputBox(“Enter your phrase”)
Label1.Text = Mid(myPhrase, 2, 6)
End Sub
* In this example, when the user clicks the command button, an input box will pop up asking the user to input a phrase. After a phrase is entered and the OK button is pressed, the label will show the extracted text starting from position 2 of the phrase and the number of characters extracted is 6.
The diagrams are shown below:
The Right function extracts the right portion of a phrase. The syntax is
Microsoft.Visualbasic.Right (“Phrase”, n)
Where n is the starting position from the right of the phase where the portion of the phrase is going to be extracted. For example:
Microsoft.Visualbasic.Right (“Visual Basic”, 4) = asic
Example 13.2: The following code extracts the right portion any phrase entered by the user.
Private Sub Button1_Click (ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myword As String
myword = TextBox1.Text
Label1.Text = Microsoft.VisualBasic.Right (myword, 4)
End Sub
13.3 The Left Function
The Left function extracts the left portion of a phrase. The syntax is
Microsoft.Visualbasic.Right (“Phrase”, n)
Where n is the starting position from the left of the phase where the portion of the phrase is going to be extracted. For example:
Microsoft.Visualbasic.Left(“Visual Basic”, 4) = asic
Example 13.3: The following code extracts the left portion any phrase entered by the user.
Private Sub Button1_Click (ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myword As String
myword = TextBox1.Text
Label1.Text = Microsoft.VisualBasic.Left (myword, 4)
End Sub
13.4 The Trim Function
The Trim function trims the empty spaces on both side of the phrase. The format is
Trim(“Phrase”)
.For example, Trim (” Visual Basic 2010 “) = Visual basic 2010
Example 13.4
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim myPhrase As String
myPhrase = Microsoft.VisualBasic.InputBox(“Enter your phrase”)
Label1.Text = Trim(myPhrase)
End Sub
13.5 The Ltrim Function
The Ltrim function trims the empty spaces of the left portion of the phrase. The syntax is
Ltrim(“Phrase”)
.For example,
Ltrim (” Visual Basic 2010 “)= Visual basic 2010
13.6 The Rtrim Function
The Rtrim function trims the empty spaces of the right portion of the phrase. The syntax is
Rtrim(“Phrase”)
.For example,
Rtrim (“Visual Basic “) = Visual Basic
13.7 The InStr function
The InStr function looks for a phrase that is embedded within the original phrase and returns the starting position of the embedded phrase. The syntax is
Instr (n, original phase, embedded phrase)
Where n is the position where the Instr function will begin to look for the embedded phrase. For example
Instr(1, “Visual Basic 2010 “,”Basic”)=8
*The function returns a numeric value.
You can write a program code as shown below:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Label1.Text = InStr(1, “Visual Basic 2010”, “Basic”)
End Sub
13.8 The Ucase and the Lcase Functions
The Ucase function converts all the characters of a string to capital letters. On the other hand, the Lcase function converts all the characters of a string to small letters.
The format is
Microsoft.VisualBasic.UCase(Phrase)
Microsoft.VisualBasic.LCase(Phrase)
For example,
Microsoft.VisualBasic.Ucase(“Visual Basic 2010”) =VISUAL BASIC 2010
Microsoft.VisualBasic.Lcase(“Visual Basic 2010”) =visual basic 2010
13.9 The Chr and the Asc functions
The Chr function returns the string that corresponds to an ASCII code while the Asc function converts an ASCII character or symbol to the corresponding ASCII code. ASCII stands for “American Standard Code for Information Interchange”. Altogether there are 255 ASCII codes and as many ASCII characters. Some of the characters may not be displayed as they may represent some actions such as the pressing of a key or produce a beep sound. The syntax of the Chr function is
Chr(charcode)
and the syntax of the Asc function is
Asc(Character)
The following are some examples:
Chr(65)=A, Chr(122)=z, Chr(37)=% ,
Asc(“B”)=66, Asc(“&”)=38
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